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A student in the 405 m-long circular track lap. Known before he ran between 4 meters per second. Beg

Murong clouds 4062010-04-12 15:10:25 +0000 #1
A student in the 405 m-long circular track lap. He is known to run before the half time of 5 meters per second, half the time after running 4 meters per second. Begged him to run half the distance how much time?
Riverside lease2010-04-12 15:14:00 +0000 #2
assume that the total time for X

X ÷ 2 × 5 + X ÷ 2 × 4 = 405 equation set

5X ÷ 2 +4 X ÷ 2 = 405

(5X +4 X) ÷ 2 = 405

9X) ÷ 2 = 405

9X = 405 × 2

9X = 810

X = 810 ÷ 9

X = 90

So half the time of 45 seconds run

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