I did not brain2010-01-31 14:01:10 +0000 #1

A. B two in a 400-meter jogging track in the ring, if running the same direction, every 10 / 3 10 minutes If you encounter a reverse run, then once every 40 seconds relative to corner, known A B run over of speed, the speed of both A and B?

rong84820302010-01-31 14:06:09 +0000 #2

My bad math

days £ Sea2010-01-31 14:37:10 +0000 #3

every 10 / 3 10 minutes What does it mean encounter time

jidegen2010-01-31 15:04:45 +0000 #4

set up a speed of X, B's rate of Y.

200 (XY) = 400

40 (X + Y) = 400

solution of equation X = 6

Y = 4

where 200 is the unit conversion come.

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