I did not brain2010-01-31 14:01:10 +0000 #1
A. B two in a 400-meter jogging track in the ring, if running the same direction, every 10 / 3 10 minutes If you encounter a reverse run, then once every 40 seconds relative to corner, known A B run over of speed, the speed of both A and B?
rong84820302010-01-31 14:06:09 +0000 #2
My bad math
days £ Sea2010-01-31 14:37:10 +0000 #3
every 10 / 3 10 minutes What does it mean encounter time
jidegen2010-01-31 15:04:45 +0000 #4
set up a speed of X, B's rate of Y.
200 (XY) = 400
40 (X + Y) = 400
solution of equation X = 6
Y = 4
where 200 is the unit conversion come.
Reply
