Sakura feng2010-02-04 01:01:17 +0000 #1

If you run the same direction, then they met over 200 sec. If turning its back running, then they met over 40 seconds, find A and B two speed.

must use a dollar linear equation solution! Thanks!

№ going against the wind2010-02-04 01:17:18 +0000 #2

because they do not know whether it was a soon as i get better soon set up in

: A speed X m / s

by: If his back turned to run, then they had 40 seconds to meet

were: B Speed (400 ÷ 40-X) m / s

by: If you run the same direction, then they had met

200 seconds were: X-(400 ÷ 40-X) = 400 ÷ 200

solution too: x = 6 (400 ÷ 40-x) = 4

lilehan972010-02-04 01:24:17 +0000 #3

set up a speed of x, then the B's speed 400/40-x

If it is a fast, equation

[x-(400/40-x) ] * 200 = 400

B if it is fast, equation

[(400/40-x)-x] * 200 = 400

Dragon Crown 1232010-02-04 02:00:22 +0000 #4

set up a speed of x, then set up a speed of x, then the B's speed 400/40-x

If it is a fast, equation

[x-(4 B if it is fast, equation 00/40-x)] * 200 = 400

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