# NBA schedule

2010-01-23 13:01:11 +0000 #1
the team 82 games a season, each of which only two divisions with another field (subject-object of a), which is I know, but the problem is 15 * 2 = 30 games, as well as 52 field is play with the same division, but 52 divided by 4 In addition to continuous ah, so I found some of the team fighting hand to hand four times, with three others fighting hand to hand, then it is determined how it is fixed or annual not the same ah?

Also, if only fighting hand to hand three times, it means that there is a team to be more than one home, then how is determined, to another not that fair?
2010-01-23 13:04:56 +0000 #2
in a different region of the 1〕 〔East Zone tournament season two, the same region in different season, a small district tournament three or four games 〔computer-generated random and which combatants spar in three games 〕, the same district in a season and compete in four races. consecutive home and away no more than six games.

specifically:

with different alliance to play two, 15 * 2 = 30

with the same coalition of 10 different districts in the four Detachment Detachment play 3 games, 4 * 3 = 12

with the same coalition of 10 different districts in the six detachment detachment playing four games, 6 * 4 = 24

with the same district teams playing 4 games, 4 * 4 = 16

30 + 12 +24 +16 = 82
, when arranging schedule, playing three games are excellent results from last season were more than a home.