# Sixth-grade math "using a hypothetical strategy to solve the problem"

2010-03-24 04:11:25 +0000 #1
5 angle and 1 yuan coins in a total of 152, of which 5 a dime more than 1 yuan coins less 50, two kinds of coins in the respective numbers of gold?
2010-03-24 04:14:41 +0000 #2
Solutions located 5 angle x, 1 Yuan y

x + y = 152

0.5x +50 = y

x + y = 152

x +100 = 2y

x = 68

y = 84
2010-03-24 04:30:52 +0000 #3
set up five corner has x gold, then the 1 yuan's are 152-x gold, 5 angle of total x / 2 yuan, 1 yuan for a 152-x yuan

were 152 -- xx / 2 = 50

x = 68
2010-03-24 04:40:10 +0000 #4
hypothetical France

because the five angle than 1 yuan less 50, if the plus 50 5 angle (both 100), then their money was the same as more then 5 angle number is 1 yuan to 2-fold,

thus gain; (152 +100) / 3 = 84

152-84 = 68

1-dollar coins 84 .5 dime 68

formula to do so:

set up five corner has x gold, then the 1 yuan's are 152-x gold, 5 angle of total x / 2 yuan, 1 yuan for a 152-x yuan

the 152-xx / 2 = 50

x = 68 152-68 = 84 (gold)