# Sixth grade math

2010-01-27 19:01:14 +0000 #1
a swimming pool 50 meters long and 25 meters wide, depth 2 meters. In the pool's sides and bottom affixed above the square decimeter of length two tiles, a total number of blocks?

The pool covers an area of many square meters?

Xiao-Hua walk along the swimming pool surrounded by two laps, a total number of meters away?
2010-01-27 19:14:17 +0000 #2
If you mean inside the wall, surrounded by the words

so 50 * 2 * 2 +25 * 2 * 2 +25 * 50 = 1550

1550/0.2 = 7750 (blocks)

A: A total of be 7750

50 * 25 = 1250 (m)

A: an area of 1250 square meters

(25 * 2 +50 * 2) * 2 = 300 (m)

A: A total of 300 meters to go

answered very carefully selected me
2010-01-27 19:43:26 +0000 #3
① 50/0.2 = 250 Kuai

25/0.2 = 2/0.2 = 125

10

total of (250 * 125 * 10) block

② 50 * 25 = 1250 Pingfang Mi

③ (50 +25) * 2 * 2 = 75 * 2 * 2 = 150 * 2 = 300 Mi
2010-01-27 19:41:14 +0000 #4
a total number of blocks:

unit not the same as a unified unit of the first two decimeter = 0.2 meters to the first count a brick an area of 0.2 X 0.2 = 0.04 Pingfang Mi

50 × 25 ÷ 0.04 +50 × 2 × 2 ÷ 0.04 +25 × 2 × 2 ÷ 0.04 = 31250 +5000 +2500 = 38750 (block)

It covers an area:

that is, ask him to the bottom area of ah!

Length X width 50 × 25 = 1250 (square meters)

total number of meters to go:

also is the desire of its perimeter ah!

(50 +25) × 2 × 2 = 300 (m)

Name:
Content: