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To improve the campus environment in the long rectangular space 80 width of 60 tennis courts, a cent

luo_ll2010-02-16 17:10:28 +0000 #1
with a quadratic Solutions
gwdmason2010-02-16 17:23:31 +0000 #2
width of the tennis courts of Y, the length of X

by the meaning of the questions:

XY = 3500

(80-X) / 2 = (60-Y) / 2

Therefore, X = 20 + Y

=> Y * Y +20 Y-3500 = 0

solution was Y1 = 50, Y2 = -70

under the meaning of the questions, Y> 0

and therefore Y = 50, X = 70

crosswalk width of 80-X = 60-Y = 10

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